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What volume of 2.0 M NaCl is required to prepare 150 mL of 0.10 M ...
Friday, March 03 15 /

Best Answer: a. 7.5 mL b/c .10 M means .10 mol/1L which in proportion is 0.10mol/1000mL=xmol/150mL which then means there are .015 moles of NaCl Then we set up a new ...

What is the initial molarity in the diluted solution? - Yahoo!7 ...
Sunday, March 03 15 /

Best Answer: molarity= number of moles/ volume (in L) 3.0 ml of the 0.25% solution contain 3 * 0.25 / 100 / 180 = 4.17 e-5 mol divide this by 0.1 L to get 4.17 * 10 ...

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Yahoo! Answers - Sol. of 14.8M of NH3. How many mL of sol should ...
Tuesday, November 11 15 /

Best Answer: M1V1=M2V2 14.8 * V1 = 0.25*100 V1 = 0.25*100/14.8 V1 = 1.689ml M1V1= M2V2 14.8*10 = M2*250 M2 = 14.8*10/250 M2 = 0.592M

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How do I make a 10 millimolar solution of HCl (in 1 Litre of Water ...
Saturday, December 12 15 /

Thanks for your answer Dr Buzz.. I calculated that at 1st but I need the HCl amount in mL. So i suspect im meant to use the V1 x M1 = V2 x M2 equation..


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Sol. of 14.8M of NH3. How many mL of sol should you dilute to make ...
Friday, November 11 15 /

Best Answer: M1V1=M2V2 14.8 * V1 = 0.25*100 V1 = 0.25*100/14.8 V1 = 1.689ml M1V1= M2V2 14.8*10 = M2*250 M2 = 14.8*10/250 M2 = 0.592M

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Updates on my research and expository papers, discussion of open problems, and other maths-related topics. By Terence Tao

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